You said "saturated", and your choice of 1000 minutes is not long enough to do that.
Ok fair enough, indeed the slowest modeled Bühlmann compartment T
1/2 is assumed as 635 minutes, so at 1000 minutes, it would be ~66% saturated (assuming that there is indeed such a 'compartment'). So we get a GF of only 53% by 1000 minutes.
I am not really accustomed to hand-calculating M values, but here goes a try...
As for final M value (which if I am not mistaken with Bühlmann is given for
pure nitrogen?)
M = M
0 + ∆M * depth [
reference]
18.9 "metres" = 12.7 "metres" + 1.0395 * 6 metres
1.89 bar
Compare that to partial pressure of nitrogen at 6 metres, which is 1.264 bar (0.79 * 1.6)?
Ok then, 1.264 bar / 1.89 bar => 0.67, or 67%
Compare the partial pressure of air
including oxygen instead, then the ambient pressure is 1.6 bar, giving 1.6 / 1.89 = 0.85, or 85%
So, are the Bühlmann M-value tables given for nitrogen pressures--as written--or for air
including its oxygen component?
Or is this math still not the way to get GF?