johndiver999
Contributor
No reread the scenario I provided, it was very explicit and was neutral (strictly for simplicity)
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There is nothing special about the submerged vessel being neutral or negative or even positive, when water displaces the internal air space the change in buoyancy is equal to the weight of the water admitted to the air space.
No reread the scenario I provided, it was very explicit and was neutral (strictly for simplicity)
If the tank is neutral in the water and then you flood it, it will then have a weight equal to the weight of the water which has been added to the inside. It is unrelated to the weight of the vessel itself...
I'd find your explanations more understandable and more compelling if you used proper units and not obsolete things like kp or incorrect things like L instead of l.Agree.
I was just trying to say that the net weight in the water would be different if it is not neutrally buoyant.
If an object has 2.1 kp (positive) buoyancy with internal air volume of 11 liters. The net buoyancy will be -8.9 (-11 + 2.1) kp as the case of AL80
If an object has -3.5 kp (negative) buoyancy with internal air volume of 10 liters. The net buoyancy will be -13.5 (-19 - 3.5) kp as the case of Steel 300 bar tank.
I'd find your explanations more understandable and more compelling if you used proper units and not obsolete things like kp or incorrect things like L instead of l.
Do you have an SMB with 18kg of lift?Clip your SMB to it and send it to the surface? Then ascend using your backup SMB.
Do you have an SMB with 18kg of lift?
That is 36-38 pounds: 18 liters or 5 gallons ....
Always challenging to work out the displacement of a bag — volume of a cylinder knowing the flat dimension…Do you have an SMB with 18kg of lift?
That is 36-38 pounds: 18 liters or 5 gallons ....