I don't think that one has gas switches though. It's an interesting question because by strictly Haldanean model if you ride your chosen M-value line continuously, you're off-gassing most efficiently the whole time. Until you change the gas.
Even with gas switches, you’re still off-gassing at max efficiency.
Hmmm... I wonder if integral supersaturation is the correct measure here... That graph does look counter-intuitive.
According to Wikipedia, "
Efficiency is the (often measurable) ability to avoid wasting materials, energy, efforts, money, and time in doing something or in producing a desired result. In a more general sense, it is the ability to do things well, successfully, and without waste."
"Without waste" means that efficiency is about finding a good spot in a cost-benefit trade-off; it does not mean "maximize speed without regard to cost." In the context of decompression, I'd say efficiency means finding the ascent with smallest DCS risk for a given TTS; or equivalently the ascent with shortest TTS for a given DCS risk. The concept of
Pareto efficiency makes sense here.
A useful metric for DCS risk comparison is integral supersaturation. Probabilistic decompression models use ISS. Finding the ascent that really minimizes ISS for a given TTS is a problem of
calculus of variations, which is quite tricky and not available in dive computers or planning software.
Following the ceiling calculated by the Bühlmann model is much easier, but is not equivalent. It limits the peak supersaturation, but ignores time and does not minimize integral supersaturation. In some trivial situations this is obvious: when decompressing with 100% oxygen, following the ceiling will only increase DCS risk but not improve off-gassing. But also after a gas switch from 18/45 to EAN50 as shown above, there are solutions that reduce ISS without increasing TTS.