Physics question from DM exam

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The question as best I can remember is as follows:

An object weighing 50 kg/125 lbs displaces 2 cubic feet of sea water and is lying in 56 feet of depth. What amount of lead (disregarding the water displaced by the mass of the lead) would be required to add 20 kg/50 lbs of negative buoyancy to the object?

I really don't see any practical application to this problem to begin with, but I'm just curious how you'd figure it out.

Going back to original post, the answer is 50lb. Just get rid of the smoke and mirrors and answer the question. The question gives you the answer.
 
I agree with both statements above. Happily, this is a question where both sides have a legitimate claim to victory.

I'm going to agree with the lawyer on this one.
 
What amount of lead (disregarding the water displaced by the mass of the lead) would be required to add 20 kg/50 lbs of negative buoyancy to the object?

If that is the intended purpose of the question, it teaches you absolutely nothing about buoyancy!
I'm not saying you're wrong, all I'm saying is that the question is useless as far as diving is concerned in that case.

I concede, how about you SB?
 
The question is...what is six times seven :)

Well I botched that question. It's actually "What is seven multiplied by nine?"
 
If that is the intended purpose of the question, it teaches you absolutely nothing about buoyancy! I'm not saying you're wrong, all I'm saying is that the question is useless as far as diving is concerned in that case.
Would not be the first time that a meaningless test question appeared on an exam (:
 
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The fact that the wrong answer has been propagated by an OW instructor (and many divers) makes me sad.

When ARE you going to admit you are wrong? The answer to the question is 50 lbs. It is not worded ambiguously at all. ***? :confused::confused::confused:
 

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