Question How does pressure increase with depth in water?

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The diagram is not accurately depicting the relative size of the movement of the two pistons.
It is pretty close if the drawing is the cross-section of cylinders.
 
In addition to what @tursiops said... because not all municipal wells produce water at rates which peak use can sustain. If you need to store water to accommodate peak flows then you might as well put it at a height which will deliver it at a suitable pressure without requiring power - or a massive pump.
I know this would come up. The systems are still oversized by a few million pounds of water if all you need to do is cover peak flows and short term power outages.

Why is this? Because you need that weight to pressurize the system. The several thousand pounds in the pipe that connects the tower to the system is not enough even if it's constantly replenished.
 
Come on people. You don't get to violate Conservation of Energy just because you add water.
 
Come on people. You don't get to violate Conservation of Energy just because you add water.
Your argument makes zero sense to me - but I'm not as smart as I once was so, if you are not completely wrong, I hope someone comes into the thread to explain why.
 
Your argument makes zero sense to me - but I'm not as smart as I once was so, if you are not completely wrong, I hope someone comes into the thread to explain why.
Which argument :)

Let me restate my initial argument using a visual aid.

PXL_20231103_033223909.jpg


In the right bottom corner of each body of water is a depth gauge. One is labeled x, the other y.

My argument is that x will show a shallower depth than y.

Edit: I should note that the "roof" of the x chamber is magically self-supporting in this scenario and so adds no pressure to the water below it.
 
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Which argument :)

Let me restate my initial argument using a visual aid.

View attachment 808882

In the right bottom corner of each body of water is a depth gauge. One is labeled x, the other y.

My argument is that x will show a shallower depth than y.
But they won't be different. Not if the water column is the same height. Do you think if you run a pipe from one to the other the water will flow out the top of the left pipe? If so, all you have to do is run a trough from the left pipe to the big tank and you have created perpetual motion. Put in a turbine and you will be rich!
 
Which argument :)

Let me restate my initial argument using a visual aid.

View attachment 808882

In the right bottom corner of each body of water is a depth gauge. One is labeled x, the other y.

My argument is that x will show a shallower depth than y.
nope, as far as I know,, the same P.
 
But they won't be different. Not if the water column is the same height. Do you think if you run a pipe from one to the other the water will flow out the top of the left pipe?
I think the pressure will settle between the initial readings of x and y.
nope, as far as I know,, the same P.
I'm sending the drawing my with son to his high school physics class tomorrow. :)

Eventually I'm going to have to do this experimentally. Unless @Tracy wants to do it first (like How does moisture enter tanks? ).
 

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