Since you know density, let’s talk about it, in relation to AL80 cylinder. You mentioned in earlier post that it would be positively buoyant (floating) even if it is full of air (at 200 bar). From physics, if an object has density greater than water, it will sink. If its density is less than water, it would float. So, let’s calculate the density of AL80 full with air at 200 bar.
Say we pick the spec of Luxfer 80 from
Scuba Cylinder Specification Chart from Huron Scuba, Ann Arbor Michigan
Outside diameter (d) = 7.25” = 18.41 cm
Cylinder height (H) = 26.06” = 66.19 cm
Dome height = half of outside diameter (r) = 1/2 d = 18.41/2 = 9.21 cm
Cylinder section height (h) = H - r = 66.19 - 9.21 = 56.98 cm
Weight empty w/o valve = 31.38 lbs = 14.25 kg
Valve weight = 2.5 lbs = 1.14 kg
Let’s calculate the weight of 200 bar air in 11.1L AL80 cavity. From ideal gas law, the air density (D) is calculated from the following equation:
D = MP/RT,
where:
D = air density in g/mL
M = molecular weight of air = 28.96 g/mol
P = air pressure = 200 bar
R = gas constant = 83.14 (mL.bar)/(K.mol)
T = ambient temperature = 25 C = 298 K
Plugging in the number into the equation,
D = 28.96 x 200 / 83.14 / 298 = 0.233 g/mL = 0.233 kg/L
W air = 0.233 kg/L x 11.1 L = 2.59 kg
Total AL80 full = empty AL80 + valve + air = 14.25 + 1.14 + 2.59 = 17.98 kg
Total outside volume of the AL80 = cylinder part + dome part.
Cylinder part = (Pi) (r) (r) (h) = 3.14 x 9.21 x 9.21 x 56.98 = 15176 mL = 15.18 L
Done part = 4/6 (Pi) (r) (r) (r) = 4/6 x 3.14 x 9.21 x 9.21 x 9.21 = 1635 mL = 1.63 L
Total AL80 outside volume = 15.18 + 1.63 = 16.81 L
Density of AL80 full = 17.98 kg / 16.81 L = 1.07 kg/L, heavier than water (1 kg/L).
Therefore, it will sink.