Hi All,
I have some dive physics questions about Lake Tahoe. I have read a lot about altitude diving, I've even had a short course, but there are a couple questions I guess I just am not smart enough to clear up on my own.
1. My computer (Oceanic Atom 3.1) read 94 feet as my depth yesterday in Lake Tahoe. I understand that this is not the actual depth, but the equivalent amount of pressure to 94 feet of seawater at sea level.
-What was my actual depth?
2. When you ascend, 15 feet in Lake Tahoe is similar to +-15 feet in Monterey, but when you reach the surface you are suddenly at 6300' elevation.
-How is this different than diving Monterey and upon surfacing, getting in a helicopter and instantly flying up to 6300'?
Thanks in advance!
At elevation, the surface air pressure is lower (about 0.82 at 6,500ft). The fresh water pressure is still 1 ATA per 34 ft / 10.5 m. So a total pressure at a real 34ft water depth is 1.82 ATA.
A lot depends on the computer (not familiar with yours). A good computer will be able to work out the actual surface pressure and actual water depth. Then a good inbuilt deco algorithm will be able to compute plans for return to the 0.82 ATA surface. But not all computers are made equal.
If we go back many years, the depth gauge was a mechanical bourdon tube design and it was not able know the surface pressure, and consequently gave depth numbers in sea level values. The depth error for this situation would be around 5ft, and that was within the accepted variation of mechanical depth instruments. The printed NDL / deco tables were also built to sea level pressures. This meant the diver needed to apply correction factors and tables to offset for the pressure differences at elevation. But good computers have now replaced this skill, and no corrections are needed.