Titanic tourist sub goes missing sparking search

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Why? Internet Archive almost certainly has a copy.
I didn't mean to sound like doing so would be an attempt to cover up. After Rob Stewart died, the FB posts about his dives were quickly deleted (which I think was an attempt to cover that up).

I found that the "our team" link is dead on the Oceangate site. (404 not found), but there's a lot more information that could be cleaned up.

I think it isn't a preposterous statement to say that Oceangate is going to close very soon. I would expect all Oceangate employees to be looking for another job. The company was mostly funded by Stockton's trust fund after all.

While I don't think that there will be government regulations addressing the causes of this accident, my hopes is that memories are maintained and that no one ignores best engineering practices in the future.

Who I really feel for is that Pakistani mother who lost a husband AND a son. She must be going completely out of her mind from grief. As a parent myself, I don't think she will ever recover, but I hope she finds a way to cope and find peace. Not sure if that is possible though from such a loss.

Honestly my question is why the comm silence about the implosion sounds being recorded by SOSUS and other ocean listening networks? James Cameron reports that those in his network knew about this Monday, and so did the USN who informed the USCG.

I understand continuing the surface search until you can confirm with the ROV but it gave a lot of people false hope that they were still alive, why?
As stated, you never stop searching until you know for certain or survival is statistically impossible.
 
And moar (that is if that is not some interior layer?)


www.reddit.com/r/WhitePeopleTwitter/comments/14h8odf/dont_drill_a_hole_into_carbon_fiber_it_ends_badly/

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My apologies, I know better than that, you're right about force and energy, of course.

But you're critique is still way off point.
I just attempted to provide the significant quantity for assessing the size of the implosion.
A lot of weird numbers were posted in this thread, none of them expressing the amount of energy. p×V, it is simple...
 
As an esoteric exercise I ran a Boyle's law calculation on the change in volume of the air in the sub at implosion

Assuming the inside of the sub was 5 feet in diameter and 15 feet long the interior volume would have been 785 cubic feet. Pressure in the sub was 14.7 psi ( normal atmospheric pressure).

If implosion depth was 11,500 feet, sea water pressure was about 5100 psi.

At the instant of implosion the internal air volume (785 cu/ft @14.7 psi) would have been compressed to 2.8 cubic feet at 5500 psi.
Not a lot of room for 5 bodies in 2.8 cubic feet. That is equal to a box about 17" x 17" x 17".
It is even worst. Your calculation is quasi-static.
And unnecessary complex. If external pressure at 4000m depth is 400 bars, the internal volume will become 1/400 of the original volume.
But the event was highly dynamic...
The shell parts were accelerated towards the center, were air and corpses were compressed. Due to inertia, the compression reaches a peak pressure several times larger than the external pressure, so in the maximum compression instant the inner pressure has peaked somewhere around 1000 bars (2.5 times the external pressure of 400 bars).
Perhaps even more.
So the inner volume of the shell was instantaneusly reduced to 1/1000 of the original value.
But as the compressed material is elastic, after reaching that very high pressure peak, the compressed material did expand back, projecting small chunks of the shell and its contents all around.
Only very hard parts, such as the titanium domes, could have survived the secondary explosion.
 
I love how far off topic this thread is .. Anyway the USA put men on the moon several times & we saved Europe from speaking German.
 
As an esoteric exercise I ran a Boyle's law calculation on the change in volume of the air in the sub at implosion

Assuming the inside of the sub was 5 feet in diameter and 15 feet long the interior volume would have been 785 cubic feet. Pressure in the sub was 14.7 psi ( normal atmospheric pressure).

If implosion depth was 11,500 feet, sea water pressure was about 5100 psi.

At the instant of implosion the internal air volume (785 cu/ft @14.7 psi) would have been compressed to 2.8 cubic feet at 5500 psi.
Not a lot of room for 5 bodies in 2.8 cubic feet. That is equal to a box about 17" x 17" x 17".
If only you'd used Bar.

Volume -- use your 785 cubic feet -- at 1 Bar (=ATA) pressurised to 400 Bar = 785/400=1.9625 CF.

Now I wonder what the temperature of that would be...
Throwing that into a calculator, the temperature would be raised from 10C / 40F to 1295C / 2363F

Not only are they instantly crushed, but they're incinerated too :(

That steam release and subsequent condensation would not help things - explosion?
 
It is even worst. Your calculation is quasi-static.
And unnecessary complex. If external pressure at 4000m depth is 400 bars, the internal volume will become 1/400 of the original volume.
But the event was highly dynamic...
The shell parts were accelerated towards the center, were air and corpses were compressed. Due to inertia, the compression reaches a peak pressure several times larger than the external pressure, so in the maximum compression instant the inner pressure has peaked somewhere around 1000 bars (2.5 times the external pressure of 400 bars).
Perhaps even more.
So the inner volume of the shell was instantaneusly reduced to 1/1000 of the original value.
But as the compressed material is elastic, after reaching that very high pressure peak, the compressed material did expand back, projecting small chunks of the shell and its contents all around.
Only very hard parts, such as the titanium domes, could have survived the secondary explosion.
Any thoughts on the heat of compression. Never mind.
 
Any thoughts on the heat of compression. Never mind.
Yeah, actually it was adiabatic compression.
So no heat exchange.
So using p×V= constant is wrong.
It is p×V^n=constant
n is around 1.4
So doing the math V2=V1×(p1/p2)^(1/1.4)
If V1 was 10 m3, at 400 bars V2 is 0.138 m3.
Regarding temperature, the adiabatic relationship is p×T^(n/(1-n))=constant.
Hence T2=T1×(p1/p2)^((1-n)/n)
If T1 was 283 K (10 °C) T2 results to be 1623 K = 1360 °C.
The corpses were vaporised instantaneously...
 
And unnecessary complex. If external pressure at 4000m depth is 400 bars, the internal volume will become 1/400 of the original volume.

And this is why I love metric.

And scuba related.. :wink:
Calculate cylinder volume in metric:
Step 1. Multiply liters x bars.
Calculate cylinder volume in imperial:
Step 1. Find somebody with a calculator


Aaaaaanyways, are memes ok yet or are we still och so serious ?
 
https://www.shearwater.com/products/swift/

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