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The linear thermal expansion coefficient of aluminium is 24E-6 K-1, so the volumetric expansion coefficient is approximately 3 times larger. For a temperature variation of 40 K (40 °C), the percentage variation of volume will be :LOL. You are a slave to minor effects and decimal points. What is the major effect of the heating? Which answer is the most correct?
If it was steel, the thermal expansion coefficient had been half that of aluminium, but the concept is the same. Metals expand significantly with heat...Where did it say it was an aluminum tank?![]()
What is the major effect of the heating?
Don't you just hate it when someone goes on at length to answer a rhetorical question?The linear thermal expansion coefficient of aluminium is 24E-6 K-1, so the volumetric expansion coefficient is approximately 3 times larger. For a temperature variation of 40 K (40 °C), the percentage variation of volume will be :
DeltaV/V = 3*24E-6*40 = 0.29% . Small, but not entirely negligible...
So also answer a) was definitely true.
The correct answer had be that both a) and c) were true.
More precisely, in both balloon and cylinder volume and pressure both increase. In the balloon, there is some small increase of pressure and a large increase of volume. In the cylinder, there is some small increase of volume and a large increase of pressure.