victorzamora
Contributor
@lowviz and @tursiops: It seems like there's a miscommunication here, but I did some fiddling with numbers and got an interesting (to me, at least) result. 1 atm is a fixed value (29.92mmHg, 14.7psi, 33.9ffw, 10mfw, etc). What's interesting, though, is that lowviz's point is actually valid but in a goofy way.
For the purposes of talking about how deep you go as a ratio of your initial pressure, it seems to equate. What I mean is: I had a question for Dan_P earlier where I equated a 30m dive from sea level (to 4ata from 1ata) to a 24m dive from 2000m of altitude (to 3.2ata from 0.8ata).....they're both 4x increases in pressure. I did a quick proof and found that, for the pressure ratio to stay constant (pressure at max depth divided by pressure at the surface), treating the ambient pressure as an "atmosphere" (different from 1atm for the purpose of this thinking) is actually mathematically accurate.
So if diving from an altitude where the barometric pressure was 0.5atm (14.96mmHg, etc), you could treat one "doubling" or "one atmosphere" (again different from the unit of measure 1atm) as 0.5atm or 5mfw or 17ffw.
For the purposes of talking about how deep you go as a ratio of your initial pressure, it seems to equate. What I mean is: I had a question for Dan_P earlier where I equated a 30m dive from sea level (to 4ata from 1ata) to a 24m dive from 2000m of altitude (to 3.2ata from 0.8ata).....they're both 4x increases in pressure. I did a quick proof and found that, for the pressure ratio to stay constant (pressure at max depth divided by pressure at the surface), treating the ambient pressure as an "atmosphere" (different from 1atm for the purpose of this thinking) is actually mathematically accurate.
So if diving from an altitude where the barometric pressure was 0.5atm (14.96mmHg, etc), you could treat one "doubling" or "one atmosphere" (again different from the unit of measure 1atm) as 0.5atm or 5mfw or 17ffw.
Your altitude calculation is back-referenced to sea level atmospheric pressure.
Diving at altitude is nothing more than changing the value that one atmosphere represents. Indeed, water does not change. So at a reduced atmosphere, it takes less depth to equal that 'atmosphere' that is sitting on top of the water. M values have to do with differences in pressure, not absolute pressures.
I read several of the preceding posts and am either impressed at the sarcasm or stunned at the confusion.
1 ATM is a unit of measure, and has exact equivalences in other systems of units.
It does NOT change with altitude, or sea level pressure.
If the surface pressure is 0.8 ATM, that does NOT mean that you get 1 ATM of water pressure above you at 8m; that amount of water only weighs enough to cause 0.8 ATM. You've got to go to 10m to get 1 ATM of water above you. and at that depth your total pressure is 1+0.8=1.8 ATM.
Please note that I said 'atmosphere', not ATM or ATA.
Thought experiment. Assume that we ascend to 380 mm Hg from the sea level 760. Half the atmospheric pressure at sea level. Dive to some great depth at that altitude and measure the pressure in pounds per sq inch. It will be very nearly the same as you would find at the same dive depth at sea level, just as John said.
Now we begin our ascent. The goal is to reach the air above the water with an appropriate gas saturation that will prevent bubbling. Even though there is the same psi at the bottom of either dive, the altitude dive is a much, much 'bigger' dive. I see this as very simply being under many more 'atmospheres' of pressure (at that dive depth when at elevation) as compared to fewer 'atmospheres' at that same dive depth when at sea level. It is nothing more than a change of reference point. You like everything referenced to sea level, it is more intuitive for me to reference to where I want to finally equilibrate. Works out the same either way.