NJMike:What I THOUGHT was....say you have an 80 cu. ft. tank on the surface. At 33' you would have half of that, since the pressure doubled...so you'd have 40 cu. ft. of air.
At 66' you'd have 1/3, or approx. 26 cu. ft. of air. At 99', 1/4 or 20 cu. ft.
So from 99' to 66', a change of 33', the volume of air would change by only 6 cu. ft.
The same change, from 33' to 0', would change by 40 cu. ft., meaning that the volume of air expands much more nearer the surface.
Am I wrong?
Actually, that's wrong since the tank is a solid container, it will still have 80 cu. ft. at any depth. Look at Boyles Law, P1V1=P2V2 or PV= K (constant)
As mentioned, the lungs are flexible, we need to fill them to the same volume, but at 33 fsw (2ata) you need twice as much surface pressure to fill them. That would mean you would go through your 80 cu. ft. in half the time you would at the surface, because you use twice the volume.
devilfish:I wasn't talking about volume, I was talking about physical size of a flexible object, diameter not volume displacement. And btw, scuba tanks don't compress
DIAMETER, no, as the volume of cylinders or balls isn't directly proportional to the diameter. But the SIZE (aka. volume) of a flexible object would be 1/2 if filled at the surface and taken to 2 ATA or 33fsw. Reverse the process from 33 fsw with the filled baloon, it will double in size (volume) at it reaches the surface, if it doesn't blow apart! Now do the math for 99 fsw to 66 fsw.
Good example Eval.