UCFKnightDiver
Contributor
Hey all,
I am interested in understanding how to better calculate the volume of gas in my cave filled LP108s. This seems particularly important when diving with a team with HP tanks. The simple calculation to do this is 108/2400*3600*2 which gives you 324cuft of gas. However, as I understand it, in the metric system, both HP130s and LP108s would be considered a 16L (or maybe it was 17L) tank and is measured by the amount of liquid the tank would hold rather than the volume of gas at a specified pressure. If the internal volume of an HP130 and LP108 is truly the same, then this would then equate to about 260-270ish cuft with the LP108s filled to 3600psi, which is a good bit less than 324cuft in the simple method above. What am I missing here, is there some reduction or additional factor I need to apply to the equation to account for diminishing returns?
I am interested in understanding how to better calculate the volume of gas in my cave filled LP108s. This seems particularly important when diving with a team with HP tanks. The simple calculation to do this is 108/2400*3600*2 which gives you 324cuft of gas. However, as I understand it, in the metric system, both HP130s and LP108s would be considered a 16L (or maybe it was 17L) tank and is measured by the amount of liquid the tank would hold rather than the volume of gas at a specified pressure. If the internal volume of an HP130 and LP108 is truly the same, then this would then equate to about 260-270ish cuft with the LP108s filled to 3600psi, which is a good bit less than 324cuft in the simple method above. What am I missing here, is there some reduction or additional factor I need to apply to the equation to account for diminishing returns?