As a diver, how does one get out of a whirlpool, descend and exit at the bottom of it?
This is a good question. If you are on the fringe, you have to swim against it. Once you get to the middle, there is a 12-20' drop down into the hole as reported by boaters. The presence of your body might be enough to disrupt the whirling action but don't count on it since boats have been sucked under.
The nearest bottom is approximately 120' under the surface where an undersea mount rises 200+ feet off the floor (but it's width is not known), separating two trenches, 350 and 400+ feet in depth.
Here's the main problem as I see it. Equalizing on the way down, should you be sucked in. Is there less pressure in the cone than the surrounding water due to the inertia of the water spinning and being kept separated? If so, what is the sudden pressure like once you get spit out on the bottom? COULD you equalize? Or would it be like getting hit with two cupped hands over your ears by Bobo the gorilla? Plus disorientation from the spinning ride down
After you get to the bottom, say 120', you have to swim past the overhead whirlpool to surface past the suction, in what I imagine would be a difficult circular current.
So to answer your question : I have no idea.
This would be an interesting question for some Dive Physiologists in the Diving Medical Forum.
Cheers-