Z factor and true capacity formula

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YuchenEasonJiang

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I'm researching the calculation of the true gas capacity based on the Z factor and ideal volume (water capacity). I noticed that some calculate the true capacity as:
True_Capacity ≈ Ideal_Capacity ÷ Z_Factor(gas & pressure@temperature) - Dive Gear Express and Teach me to dive


But according to the formula PV=ZnrT, true capacity should equal to ideal capacity times Z factor, rather than divided by.
So, I have a question: How do you calculate the true capacity? Multiply divided by Z factor?
 
Z factors increase as pressure increases.
Ideal divided by Z to equal a smaller actual or true is correct. DGX's formula is correct.

The Vs in these are in PVideal=nrT or PVactual=ZnrT. Moving things around you get...

V/Z = nrtT/P. If n, r, T, and P are all held constant then Videal/Z = Vtrue
 
True Capacity = Ideal Capacity / Z is correct
Z is typically > 1 for gasses & pressures we care about. For example, Z(air, 3000 psi) = 1.032 from the DGX link.

It may help to know that Z is *defined* as Z=PV/(nRT), where P and n are both the actual or measured quantities. V is always actual, since it's a rigid vessel.

At 3000 psi, the molecules don't compress as well, so fewer are required (n is smaller than in the ideal case) to yield a given pressure when in a given volume container.

ETA: I failed to connect the dots previously: Ideal Capacity = PV. True capacity is defined as the volume that non-ideal gas would occupy at 1 atm pressure. Conveniently, air behaves as an ideal gas at 1 atm(^), therefore PV (after expanding to 1 atm) = 1 * Real Capacity = nRT. From the above definition of Z, we see that
Z = Ideal Capacity / Real Capacity or equivalently​
Real Capacity = Ideal Capacity / Z​

(^) for our purposes, find Z(air, 1 atm) in a table and observe the value 1.0.
 
 
https://www.shearwater.com/products/teric/
http://cavediveflorida.com/Rum_House.htm

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