halocline
Contributor
If I understand correctly, in use there is always air on one side of the diaphragm (inside) and always water on the other. (outside) Enough air enters the case to equalize (along with the spring force?) against the ambient water pressure on the diaphragm. When you inhale, you lower the inside air pressure, which allows the water to push in the diaphragm, opening the lever, etc...
Okay, so why isn't the explanation like this?
When swimming normally, the water is on the underside of the diaphragm, and the buoyant air is above. When you inhale, the air flows upward away from the diaphragm. But when you're inverted, looking up at the surface, the buoyant air is underneath the inside of the diaphragm, pushing up, which makes it more difficult to pull the diaphragm "down" to open the valve.
I'm not sure I understand the influence of the exhaust valve on this, as what I've experienced is an increase in inhalation, not exhalation. I'm sure I'm oversimplifying!
Okay, so why isn't the explanation like this?
When swimming normally, the water is on the underside of the diaphragm, and the buoyant air is above. When you inhale, the air flows upward away from the diaphragm. But when you're inverted, looking up at the surface, the buoyant air is underneath the inside of the diaphragm, pushing up, which makes it more difficult to pull the diaphragm "down" to open the valve.
I'm not sure I understand the influence of the exhaust valve on this, as what I've experienced is an increase in inhalation, not exhalation. I'm sure I'm oversimplifying!