I'm not familiar with metric units or tanks, but I do know that they are measured in water volume. So if you assume that the wall thickness is negligible/proportional then the 10l tank has 4 liters less volume than the 14l, this will make you less buoyant by 4 liters.
Now the tank weighs 4 kgs less, so in essense, you have less weight which increases your buoyancy by 4 kgs.
So far, this approximately cancels each other out (1 liter water ~ 1 kg).
The remaining factor is the weight of the gas in the tank- if you assume a minimal amount of gas at the safety stop, then the weighting should be about the same. If you did one safety stop with a nearly empty tank and the next dive with a nearly full one, then the difference will be the weight of 10 liters of compressed gas, whatever that is. You have to add the weight of 10 liters of gas to be able to hold your stop.
The one approximation that I'm uneasy about is the 1 liter water ~ 1 kg. In the real world, it might be close enough to weight people, but within the scope of this problem it could make the difference between adding/removing weight. If the 1 liter of water weighs more than 1 kg, then you'll have to remove weight, and vice versa.
So how does that sound so far, and what does 10 liters of gas weigh? It will be the difference between the empty weight of the 14 liter tank and the empty weight of the 10 liter tank minus the 4 kgs (assuming that the 4 kgs difference is between an empty 14 l and a full 10 l). Now all we need to know is the specs on the tank.

Does all this sound reasonable?
I edited this to make this academic problem more applicable to the real world.

Pretend that you do the first dive with a 14 L tank and then have to change tanks and reweight for the second dive. And I also botched the part about the weight of the gas.