Help with density

[rakkis]

6 volumes of gas in a flexible container at 1 ata will be 3 volumes of gas when you bring that container with you to a pressure of 2 ata.

This is certainly correct.

But then you had a brain fart and said:

The ratio of the final volume to the initial volume was 2/6, i.e. 1/3.

When it should have been 3(volume at depth)/6(surface volume). i.e. 1/2. Which is the relationship you correctly described before your brain fart

You misrepresent what I said (perhaps due to not following what I said).

I understood the text fine, it just didn't match with the numbers that followed. Hence, my clarification.

 

[rakkis]

Volume halves. Density ... doubles, which, again, is precisely what I said. (The day I get ideal gas laws wrong is likely to be the day *after* the day I start drinking.)

Actually no, you said:

The ratio of the final density to the initial density is ... 3"

 

[ClayJar]

Hehe, go figure. That's what you get for working in greek letters too much. Those wacky numerals get you.

I'm much better writing equations on paper. Hmm... does this forum support a math markup language?

(Incidentally, when I said that's what I said, I was referring to the inverseness, not the values. When I'm tired and haven't eaten, and I've got a cat camping on my lap, I can get arithmetic wrong, but the physics I can do even at 3am with *two* cats on my lap.)

 

[TheHobster]

Screw it, lets just dive!!