mccabejc:
Does anyone understand the concepts and equations well enough to give me a short synopsis?
The classical model is that the human body is modeled as series of 'compartments' that fill (and empty) at different rates. Further, each compartment has maximum saturation value that it can tolerate back at the surface, and the rule of thumb is that the faster the compartment, the higher this value is.
Okay, let's take a super-KISSed example:
I'm going to invent a 2 compartment model. We'll say that Compartment F (for Fast) has a 5 minute halftime and Compartment S (for Slow) has as 60 minute halftime. I'll show how halftimes work in a minute.
Next, we're going to assume all of our ascents and decents are instant. Its not realistic, but it makes this all a lot simpler to understand.
Finally, we're going to assume that the Maximum value that F and S can have without you getting bent back at the surface are F=70 and S=20. These maximum values for each compartment are called "M-values", and are often fudged by a dive computer manufacturer to add conservatism (safety margin). Exceeding one of these M-values during a dive isn't fatal - - it just means we've gone over the no-deco limit and into decompression.
Okay, at the beginning of the dive, time=0, depth=0, F=0 and S=0.
We jump in and immediately teleport to 90fsw (d=90).
After 5 minutes, Compartment F has seen one full "halftime" (because time=halftim). This means that it has filled halfway between where it was and the value at which it would reach a new equilibrium. I'm assuming these M-value numbers are equivalent to depth in feet, so here, it goes to halfway between 0 and 90, so its value is (5min/5min)*(90-0)/2 = 45.
Meantime, Compartment S has seen 5/60ths of its halftime, so it will have gone 1/12th of halfway: that would be (5min/60min)*(90-0)/2 = 4
Summary: t=5, d=90, F=45, S=4.
We stay another 5 minutes. So we take our current Compartment loadings (45 and 4) and add on their additional halftime loadings.
EDIT: I really did this above too, but since our starting values were zero, I was lazy and didn't bother to show it in the math.
F = 45 + (5/5)*(90 - 45)/2 = 67.5
S = 4 + (5/60)*((90 - 4)/2) = 8
Summary: t=10, d=90, F=67.5, S=8.
The math looks a bit yucky, but its simple: you're taking the current balance and adding to it the appropriate halftime fraction...FWIW, it might be easier to understand it if I rewrite the formula this way:
Compartment = PriorBal + (TimeSpent/CompartmentTimeDefinition) * (depth - PriorBal)/2 = NewBalance
...the division by2 in this formula is because it works in halftimes. If you had nuclear physics in school, you'll remember this concept as "half-life" for atomic decay.
Okay, at this point, our F is getting close to its M-value of 70, so we're probably down to just a few more minutes before we're into Deco...so we decide its time to ascend.
Ascending to depth 50ft: t=10, d=50, F=67.5, S=8.
We're now going to spend 5 minutes here.
F = 67.5 + (5/5)*(50 - 67.5)/2 = 58.75 (lower!)
S = 8 + (5/60)*((50 - 8)/2) = 10 (higher)
Summary: t=15, d=50, F=59, S=10.
What happened here is that because F > d, this meant that the Fast compartment started to offgas, and because S < d, the Slow compartment continued to load.
And since our dive computer will calculate "time remaining" based on all of this, it will tell you that you have more bottom time...at least for now. This is because what's called the "Controlling Compartment" (for your no-stop time) changed. Here, we had little choice: it went from F to S.
Lets skip ahead and assume we've run these numbers for around ten more 5 minute chunks and that we're now at:
t=65, d=50, F=~50, S=~18 ...and now the slow compartment says we're out of no-deco time, so its time to ascend to the surface.
We first have to see if its safe to come to the surface. Since we kept things no-deco, it should be, but we'll check anyway:
F= ~50 (below its M-value of 70: safe to surface), S= ~18 (below its M-value of 20: safe to surface).
Okay, we're now at the surface. When we arrive, we're at: t=65, d=0, F=50, S=18.
During our surface interval, if our model was perfectly symmetrical, then the same rules would apply for our off-gassing. Let's assume it is and give our SI its first 5 minutes:
t=70, d=0 and:
F = 50 + (5/5)(0 - 50)/2 = 25 (that dropped a lot)
S = 10 + (5/60)(0 - 10)/2 = 9.6 (that dropped only a little).
And so on. If you followed the basic concept here, then you're ready to dip underwater to see the rest of the iceburg of decocompression modeling.
-hh