MonkSeal:
It's not a direct proportion. It's rather exponential function that's used to describe the model.
Monkseal,
I understand the mathematics of half-times - by their purest definition, they never reach zero, which is what the question was about, and Diver0001's equation about. There is no exponential function in Diver0001's equation to reach zero. By pure application of half-times, 6 half-time or half-life cycles starting with 640 minutes results in 10 minutes still remaining. This is (rounded) 1.6% of the original value of 640 minutes. This can be demonstrated a series of simple calculations.
640 / 2 = 320 (first half-time or half-life)
320 / 2 = 160 (second half-time of half-life)
160 / 2 = 80 (third half-time or half-life)
80 / 2 = 40 (fourth half-time or half-life)
40 / 2 = 20 (fifth half-time or half-life)
20 / 2 = 10 (sixth half-time or half-life)
Or exponentially,
640 / (2^6) = 10
The only number divided by 2 which will equal zero is zero itself. Using the exponential approach solely, a compartment that is ever once not at zero can never return to zero.
The distinction becomes when mathematically the asypmtotic approach to zero is defined as close enough to zero to call zero. Diver0001's equation and verbiage is clear on that.
What value do you use Monkseal, and what terms is it couched in (number of cycles, % of original value, etc.)?