Think "Helium." Unless told to do so, it isn't somerhing they'd test for, and it's oderless, tasteless etc...Genesis once bubbled...
Even so, 1% O2? How?
If the guy was a homebrewer...
Rick
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Think "Helium." Unless told to do so, it isn't somerhing they'd test for, and it's oderless, tasteless etc...Genesis once bubbled...
Even so, 1% O2? How?
We occasionally run into a classic example which needs to be mentioned. In one fatality the victim was using a 38 cubic foot surplus oxygen cylinder. The investigator reported as the follaws: "The regulator had rust and salt water residue in the first stage. The tank contained five quarts of rusty salt water with one-half inch of rust sediment." In this instance the victim was probably doomed before entering the water. If he didn't "buy it" on this dive he probably would on the next dive, if the tank didn't explode the next time it was charged.
John J. McAniff, "National Accident Data Analysis," Proceedings of the Eighth International Conference on Underwater Education, IQ8, Sponsored by the National Association of Underwater Instructiors, Nov. 5-7, 1976, Addendum, pg 45.
The only case in which the condition of the air supply gear was definitely implicated in a death involved a 38 ft3 surplus report: "The regulator had rust and salt water residue in the first stage. The tank had five quarts of rusty salt water in it, with one half inch rust sediment present." Since this tank had 700 lb/in2 remaining and the victim was diving alone, oru presumption is that the victim performed some moneuver in the water that dumped residue into his regulator and either locked it up or flooded his mouth and lungs with rust and water...
United States Underwater Fatality Statistics 1975, March 1977, pg 27
The electrons provided from both oxidation steps are used to reduce oxygen as shown.
O2 (g) + 2 H2O + 4e- ------> 4 OH-
The ferric ions then combine with oxygen to form ferric oxide [iron (III) oxide] which is then hydrated with varying amounts of water. The overall equation for the rust formation may be written as :
4Fe+2 (aqueous) + O2 (gas) [4 + 2 H20] -----> 2Fe2O3 X 2H2O (solid) + 8 H+ (aqueous)