What if the 40 was partially full and rated for 2400 psi?
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MikeFerrara once bubbled...
What if the 40 was partially full and rated for 2400 psi?
Well if the 40 had 600psi in it to start and the 80 3000psiMikeFerrara once bubbled...
What if the 40 was partially full and rated for 2400 psi?
If the 40 brings 10 cf to the table at 600psi and the 80 brings 80 at 3000psi the there are 90cf total.Uncle Pug once bubbled...
Which would give 34.6 in the 40
and 55.4 in the 80
Is this correct?
Uncle Pug once bubbled...
Well if the 40 had 600psi in it to start and the 80 3000psi
then 2/3 of 3600psi (3000+600) would be 2400 psi. final pressure.
and since the 80 at 3600 would have 20% more in it then we would be looking at 2/3 of 96 or 64cf
So the 80 would have 64cf and the 40 would have 40cf and they both would be at 2400 psi.
Am I close?
Uncle Pug once bubbled...
Now if I use the Sheck33 formula:
P1 x V1 + P2 x V2 = P3 x V3
3000X.392 + 600X.245=P3X.637
1323/.637=2077psi
Which would give 34.6 in the 40
and 55.4 in the 80
Is this correct?
Math is easy once you understand.... NOT.... gggaaaakkkkk....TexasMike once bubbled...
after all of the above...I do need to find better uses of random brain power....