Captain Andy
Registered
Greetings,
I saw an interesting thread re a Li Po conversation to a UV-26. This got me started thinking about my seldom used UV-18. I'm one of the old guys with an old scooter that's kinda heavy to lug around the boat and even worse loading it in the truck! Seems like everyone has newer lighter.scoots so, if I could save weight on the batteries and cut the tube down, I could have a more user friendly scooter.
Here is where the math comes in.
The current tube is 10.6" x 28" that's 2462 cu in or 1.429 cu ft
Fw is 62.3 # per cu ft so I should have 89.02# of positive buoyancy ( not sure of how to word that).
The existing batteries weigh 11.9 # s each and the LiPo weigh 3 #s each so I should shed 17.8#s
89.02-17.8=71.22#s
1.143 cu ft
.286 cu ft
494.2 cu in
The tube is 88.2 cu in per inch of length.
62.3 / 1728=.036 # per cu in
494*.036=5.6
So if I take 5.6" off the tube length I should be neutral in fw.
Ok gloves off. Tell me where I screwed up please.
Thanks in advance,
Andy
I saw an interesting thread re a Li Po conversation to a UV-26. This got me started thinking about my seldom used UV-18. I'm one of the old guys with an old scooter that's kinda heavy to lug around the boat and even worse loading it in the truck! Seems like everyone has newer lighter.scoots so, if I could save weight on the batteries and cut the tube down, I could have a more user friendly scooter.
Here is where the math comes in.
The current tube is 10.6" x 28" that's 2462 cu in or 1.429 cu ft
Fw is 62.3 # per cu ft so I should have 89.02# of positive buoyancy ( not sure of how to word that).
The existing batteries weigh 11.9 # s each and the LiPo weigh 3 #s each so I should shed 17.8#s
89.02-17.8=71.22#s
1.143 cu ft
.286 cu ft
494.2 cu in
The tube is 88.2 cu in per inch of length.
62.3 / 1728=.036 # per cu in
494*.036=5.6
So if I take 5.6" off the tube length I should be neutral in fw.
Ok gloves off. Tell me where I screwed up please.
Thanks in advance,
Andy